現在探討有個凸輪,
開始時先在0°至100°區間滯留之後提升,
並且在200°至260°區間再次滯留,
其高度(衝程)為5公分,
其餘260°至360°則為返程。
升程採用等加速度運動,
返程之運動型式若為等速度運動的話,
則利用dewell()及plot_dewell()兩個程式,
以每10°計算一次,
並繪出其位置、速度、加速度與凸輪迴轉角度的關係圖:
>> plot_dwell(0:10:360,5,[2 1],[100 200 260])
y =
Columns 1 through 3
0 0 0
Columns 4 through 6
0 0 0
Columns 7 through 9
0 0 0
Columns 10 through 12
0 0 0.0200
Columns 13 through 15
0.0800 0.1800 0.3200
Columns 16 through 18
0.5000 0.6800 0.8200
Columns 19 through 21
0.9200 0.9800 1.0000
Columns 22 through 24
1.0000 1.0000 1.0000
Columns 25 through 27
1.0000 1.0000 1.0000
Columns 28 through 30
0.9000 0.8000 0.7000
Columns 31 through 33
0.6000 0.5000 0.4000
Columns 34 through 36
0.3000 0.2000 0.1000
Column 37
0
yy =
Columns 1 through 3
0 0 0
Columns 4 through 6
0 0 0
Columns 7 through 9
0 0 0
Columns 10 through 12
0 2.2918 2.5210
Columns 13 through 15
2.7502 2.9794 3.2086
Columns 16 through 18
1.1459 0.9167 0.6875
Columns 19 through 21
0.4584 0.2292 0
Columns 22 through 24
0 0 0
Columns 25 through 27
0 0 -0.5730
Columns 28 through 30
-0.5730 -0.5730 -0.5730
Columns 31 through 33
-0.5730 -0.5730 -0.5730
Columns 34 through 36
-0.5730 -0.5730 -0.5730
Column 37
-0.5730
yyy =
Columns 1 through 3
0 0 0
Columns 4 through 6
0 0 0
Columns 7 through 9
0 0 0
Columns 10 through 12
0 1.3131 1.3131
Columns 13 through 15
1.3131 1.3131 1.3131
Columns 16 through 18
-1.3131 -1.3131 -1.3131
Columns 19 through 21
-1.3131 -1.3131 0
Columns 22 through 24
0 0 0
Columns 25 through 27
0 0 0
Columns 28 through 30
0 0 0
Columns 31 through 33
0 0 0
Columns 34 through 36
0 0 0
Column 37
0
h1 =
152.0099
153.0089
154.0089

y為從動件在不同迴轉角度,
垂直移動的高度。
yy為從動件的垂直運動速度。
yyy為從動件的垂直加速度。
題目二:
若今天有一個凸輪半徑15㎝,
以順時針方向旋轉。
從動件為梢型,
垂直接觸凸輪,
長為10㎝。
從動件之運動依照上一題之運動型式,
100°~200°、260°~360°各為升程及返程時的對應迴轉角度。
升程為等加速度運動,
返程仍設定為等速運動。
則透過pincam()來繪製工作圖:
>> [x y]=pincam([0:10:360],15,5,0,10,[100 200 260],[2 1],-1)
x =
Columns 1 through 3
15.0000 14.7721 14.0954
Columns 4 through 6
12.9904 11.4907 9.6418
Columns 7 through 9
7.5000 5.1303 2.6047
Columns 10 through 12
0.0000 -2.6047 -5.1645
Columns 13 through 15
-7.7000 -10.2203 -12.7163
Columns 16 through 18
-15.1554 -17.2903 -18.8098
Columns 19 through 21
-19.6000 -19.5977 -18.7939
Columns 22 through 24
-17.3205 -15.3209 -12.8558
Columns 25 through 27
-10.0000 -6.8404 -3.4730
Columns 28 through 30
-0.0000 3.2993 6.3274
Columns 31 through 33
9.0000 11.2488 13.0228
Columns 34 through 36
14.2894 15.0351 15.2645
Column 37
15.0000
y =
Columns 1 through 3
0 2.6047 5.1303
Columns 4 through 6
7.5000 9.6418 11.4907
Columns 7 through 9
12.9904 14.0954 14.7721
Columns 10 through 12
15.0000 14.7721 14.1894
Columns 13 through 15
13.3368 12.1801 10.6703
Columns 16 through 18
8.7500 6.2932 3.3167
Columns 19 through 21
0.0000 -3.4556 -6.8404
Columns 22 through 24
-10.0000 -12.8558 -15.3209
Columns 25 through 27
-17.3205 -18.7939 -19.6962
Columns 28 through 30
-19.5000 -18.7113 -17.3843
Columns 31 through 33
-15.5885 -13.4058 -10.9274
Columns 34 through 36
-8.2500 -5.4723 -2.6915
Column 37
-0.0000

所計算出來各對應的值,
為梢型從動件和凸輪接觸的座標。
因為偏置為零,
故所有從動件之延長線,
均會交於基圓的圓心。
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